{"id":114808,"date":"2024-03-28T15:00:00","date_gmt":"2024-03-28T18:00:00","guid":{"rendered":"https:\/\/vestibulares.estrategia.com\/portal\/?p=114808"},"modified":"2024-09-23T14:01:32","modified_gmt":"2024-09-23T17:01:32","slug":"lancamento-horizontal","status":"publish","type":"post","link":"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/lancamento-horizontal\/","title":{"rendered":"Lan\u00e7amento horizontal: conceito, f\u00f3rmulas e quest\u00f5es"},"content":{"rendered":"<p class=\"wp-block-paragraph\">O <span id=\"urn:local-annotation-675585\" class=\"textannotation disambiguated\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/lancamento-horizontal\">lan&ccedil;amento horizontal<\/span> de um objeto acontece quando ele &eacute; liberado na dire&ccedil;&atilde;o horizontal a uma determinada dist&acirc;ncia do solo. Trata-se de um movimento composto entre uma queda livre no sentido vertical e um deslocamento uniforme na horizontal, como ser&aacute; demonstrado neste artigo.&nbsp;<p class=\"wp-block-paragraph\">Em muitos vestibulares, as provas de <span id=\"urn:enhancement-e0da1198-8352-44be-9fa5-d00087e5e534\" class=\"textannotation disambiguated wl-creative-work\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/fisica\">f&iacute;sica<\/span> cobram conhecimentos espec&iacute;ficos sobre a <span id=\"urn:enhancement-7701ba55-b457-46d7-b235-2cd3b4ddbf50\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/cinematica\">cinem&aacute;tica<\/span> e <span id=\"urn:enhancement-51dd0674-a7f2-400d-a04e-f9f67e451e47\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/dinamica\">din&acirc;mica<\/span> dos objetos em seus deslocamentos no espa&ccedil;o. O lan&ccedil;amento horizontal est&aacute; entre os temas que aparecem em quest&otilde;es de segunda fase ou ainda em enunciados de maior complexidade no Enem. Se quer conhecer mais sobre o tema e preparar uma base te&oacute;rica para resolver esse tipo de exerc&iacute;cio, continue lendo este artigo.<\/p><div id=\"ez-toc-container\" class=\"ez-toc-v2_0_86 counter-hierarchy ez-toc-counter ez-toc-transparent ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\"><p class=\"ez-toc-title\" style=\"cursor:inherit\">Navegue pelo conte\u00fado<\/p>\n<\/div><nav><ul class='ez-toc-list ez-toc-list-level-1 ' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/lancamento-horizontal\/#O-que-e-lancamento-horizontal\" >O que &eacute; lan&ccedil;amento horizontal?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/lancamento-horizontal\/#Formulas-do-lancamento-horizontal\" >F&oacute;rmulas do lan&ccedil;amento horizontal<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/lancamento-horizontal\/#Questao-sobre-lancamento-horizontal\" >Quest&atilde;o sobre lan&ccedil;amento horizontal<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/lancamento-horizontal\/#Estude-para-as-provas-com-a-Coruja\" >Estude para as provas com a Coruja!<\/a><\/li><\/ul><\/nav><\/div>\n<h2 class=\"wp-block-heading\" id=\"h-o-que-e-lancamento-horizontal\"><span class=\"ez-toc-section\" id=\"O-que-e-lancamento-horizontal\"><\/span>O que &eacute; lan&ccedil;amento horizontal?<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Um <a href=\"https:\/\/www.youtube.com\/watch?v=AHMJBMFxzJE&amp;pp=ygUmbGFuw6dhbWVudG8gaG9yaXpvbnRhbCBlc3RyYXRldmlhIHZlc3Q%3D\" target=\"_blank\">lan&ccedil;amento horizontal <\/a>acontece quando um objeto &eacute; lan&ccedil;ado a partir de uma certa altura, de uma <span id=\"urn:enhancement-3b93653c-ab88-442a-b0df-35d0bfeb9e62\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span> constante, que possui um vetor horizontal, com sentidos que variam entre direita e esquerda. Ao mesmo tempo em que o movimento ocorre horizontalmente, h&aacute; uma queda em altura acontecendo.&nbsp;<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/r5dUeavAese_gr5I4fyABKdhlW0TQhBIMXOhc9yizXdOp2Eb3Ro-J-K7wtsXDAeciMXoAUxsUwonjBtzLdoz9CtgYshxChf-4zG98Z52VjYoeAP6PXwG7Lp1-_AOMQVdNAqpl8TQ3YUZ7xh5ATC8S6s\" alt=\"Lan&ccedil;amento horizontal\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">O deslocamento do corpo &eacute; influenciado pela acelera&ccedil;&atilde;o da <span id=\"urn:enhancement-e8fe0d6e-bab8-4d40-a1cf-45ebfcf11979\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/gravidade\">gravidade<\/span>, isso significa que o vetor <span id=\"urn:enhancement-f8a740e6-e253-4fe4-a975-1b4726a717d1\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span>, no <span id=\"urn:enhancement-5b8ebf04-a1e5-4036-a735-8f764b3b7222\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/eixo-de-rotacao\">eixo<\/span> vertical, possui uma intensidade vari&aacute;vel ao longo da <span id=\"urn:enhancement-827b5884-a270-4fc0-a611-712cc878cfae\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/trajetoria\">trajet&oacute;ria<\/span>. Em <span id=\"urn:enhancement-59112732-6da3-4ee9-8738-91cbaede91d8\" class=\"textannotation disambiguated wl-creative-work\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/fisica\">f&iacute;sica<\/span>, a queda de um objeto no sentido vertical, sob a&ccedil;&atilde;o da <span id=\"urn:enhancement-0d6f93d1-910d-47d3-9020-4346ba296b0d\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/gravidade\">gravidade<\/span>, &eacute; chamada de <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/queda-livre\/\" target=\"_blank\">queda livre<\/a>.<\/p><p class=\"wp-block-paragraph\">Diante dessas informa&ccedil;&otilde;es, pode-se afirmar que o lan&ccedil;amento horizontal &eacute; um deslocamento composto por dois elementos principais: um movimento uniforme (MU) que ocorre no <span id=\"urn:enhancement-0bcaeffe-9ef1-4932-94fc-d63ed86d4c20\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/eixo-de-rotacao\">eixo<\/span> horizontal da <span id=\"urn:enhancement-2013fbfb-c44c-408d-b258-c6fed134f874\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/trajetoria\">trajet&oacute;ria<\/span>, enquanto o percurso vertical &eacute; um <span id=\"urn:enhancement-fdb06a1e-cde5-4581-a9af-89cf53ef3ce8\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/muv\">movimento uniformemente variado<\/span> (<span id=\"urn:enhancement-1e2c1d2f-b35d-48c2-aaef-98b5fad37883\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/muv\">MUV<\/span>).&nbsp;<\/p><h2 class=\"wp-block-heading\" id=\"h-formulas-do-lancamento-horizontal\"><span class=\"ez-toc-section\" id=\"Formulas-do-lancamento-horizontal\"><\/span>F&oacute;rmulas do lan&ccedil;amento horizontal<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Se o lan&ccedil;amento horizontal &eacute; um movimento composto, para a compreens&atilde;o b&aacute;sica do deslocamento do corpo, a forma mais direta de estudar seus componentes &eacute; separadamente, considerando a peculiaridade e estilo dos movimentos nos <span id=\"urn:enhancement-03c0739e-7690-4be8-b707-f81e33d6031e\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/coordenadas-cartesianas\">eixos<\/span> horizontal e vertical.&nbsp;<\/p><h3 class=\"wp-block-heading\" id=\"h-movimento-horizontal-nbsp\">Movimento horizontal&nbsp;<\/h3><p class=\"wp-block-paragraph\">Como o movimento horizontal parte de uma <span id=\"urn:enhancement-0cc112ea-28ea-4726-a964-b4fa9bcc0c8c\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span> constante de lan&ccedil;amento, &eacute; considerado um deslocamento uniforme ao longo do tempo. Ent&atilde;o, ser&atilde;o aplicadas as f&oacute;rmulas utilizadas no estudo do MU.&nbsp;<\/p><p class=\"has-text-align-center wp-block-paragraph\">S(t) = S<sub>0<\/sub> + V<sub>0<\/sub>.t&nbsp;<\/p><ul class=\"wp-block-list\">\n<li>S(t) &eacute; a posi&ccedil;&atilde;o no espa&ccedil;o em fun&ccedil;&atilde;o do tempo;<\/li>\n\n\n\n<li>S<sub>0<\/sub> &eacute; a localiza&ccedil;&atilde;o inicial do corpo no eixo de movimento;<\/li>\n\n\n\n<li>V<sub>0<\/sub> representa a velocidade inicial (e constante) do deslocamento horizontal; e<\/li>\n\n\n\n<li>t representa o tempo decorrido no momento estudado.<\/li>\n<\/ul><p class=\"wp-block-paragraph\">No estudo da <span id=\"urn:enhancement-298c9058-763a-4fc9-83ce-16a6a12b46f6\" class=\"textannotation disambiguated wl-creative-work\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/fisica\">f&iacute;sica<\/span>, os referenciais podem ser criados de forma que facilitam o desenvolvimento dos c&aacute;lculos. Assim, se adotarmos a posi&ccedil;&atilde;o inicial como o marco zero do <span id=\"urn:enhancement-837843d5-6f3d-480f-b544-ab981b311485\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/eixo-de-rotacao\">eixo<\/span> de refer&ecirc;ncia (S<sub>0<\/sub> = 0), a f&oacute;rmula se reduz a S(t) = V<sub>0<\/sub>.t.<\/p><p class=\"wp-block-paragraph\">&Eacute; importante observar que o estudo do lan&ccedil;amento horizontal pode ser realizado com base em um <span id=\"urn:enhancement-a33f803d-90bc-4eda-88fa-6f37aa71da8a\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/plano-cartesiano\">plano cartesiano<\/span>, de maneira que a posi&ccedil;&atilde;o horizontal seja referenciada no <span id=\"urn:enhancement-fd80f5be-bdbd-4242-8cc5-8722d44b47cf\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/eixo-de-rotacao\">eixo<\/span> x. Nesse caso a f&oacute;rmula pode ser descrita como: x(t) = V<sub>0<\/sub>.t.<\/p><h3 class=\"wp-block-heading\" id=\"h-movimento-vertical-nbsp\">Movimento vertical&nbsp;<\/h3><p class=\"wp-block-paragraph\">No <span id=\"urn:enhancement-ddbebb62-7415-49ff-859e-972271933e57\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/eixo-de-rotacao\">eixo<\/span> vertical de um lan&ccedil;amento horizontal, por sua vez, o deslocamento respeita as leis do <span id=\"urn:enhancement-269d2ff2-63b3-4a15-8149-7854e6a2340f\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/muv\">MUV<\/span>. Isso significa que a acelera&ccedil;&atilde;o deve ser considerada nos c&aacute;lculos, nesse caso, a acelera&ccedil;&atilde;o da <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/gravidade\/\" target=\"_blank\">gravidade<\/a>.<\/p><p class=\"has-text-align-center wp-block-paragraph\">S(t) = S<sub>0<\/sub> + V<sub>0<\/sub>.t + (a.t<sup>2<\/sup>)\/2<\/p><ul class=\"wp-block-list\">\n<li>S(t) &eacute; a posi&ccedil;&atilde;o no espa&ccedil;o em fun&ccedil;&atilde;o do tempo;<\/li>\n\n\n\n<li>S<sub>0<\/sub> &eacute; a localiza&ccedil;&atilde;o inicial do corpo no eixo vertical;<\/li>\n\n\n\n<li>V<sub>0<\/sub> &eacute; a intensidade da velocidade vertical inicial;<\/li>\n\n\n\n<li>a &eacute; a acelera&ccedil;&atilde;o que atua sobre o corpo;<\/li>\n\n\n\n<li>t representa o tempo decorrido.<\/li>\n<\/ul><p class=\"wp-block-paragraph\">Novamente, &eacute; poss&iacute;vel observar que o lan&ccedil;amento horizontal tem uma <span id=\"urn:enhancement-6f161718-deca-4088-abdf-c7bdf3ec7114\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span> inicial unicamente na horizontal, que &eacute; nula na dire&ccedil;&atilde;o vertical. Assim, V<sub>0<\/sub>=0 e, conforme a refer&ecirc;ncia adotada S<sub>0<\/sub>, o que simplifica a f&oacute;rmula em: S(t) = (a.t<sup>2<\/sup>)\/2.<\/p><p class=\"wp-block-paragraph\">Nesse caso, &eacute; importante lembrar que a acelera&ccedil;&atilde;o que atua sobre o objeto &eacute; a <span id=\"urn:enhancement-8a4f4ecd-8cfb-4680-b4e1-51c605addca1\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/gravidade\">gravidade<\/span> (a=g). Por fim, no <span id=\"urn:enhancement-c5add9c8-df81-40c6-ac79-89e0075acdcd\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/plano-cartesiano\">plano cartesiano<\/span>, a posi&ccedil;&atilde;o vertical do objeto ser&aacute; referida por y, assim, o <span id=\"urn:enhancement-5739ddb8-8744-47d5-a3ee-8667e2d6f88a\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/calculo-matematico\">c&aacute;lculo matem&aacute;tico<\/span> pode ser descrito como y(t)=(g.t<sup>2<\/sup>)\/2.<\/p><h2 class=\"wp-block-heading\" id=\"h-questao-sobre-lancamento-horizontal\"><span class=\"ez-toc-section\" id=\"Questao-sobre-lancamento-horizontal\"><\/span>Quest&atilde;o sobre lan&ccedil;amento horizontal<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Universidade Estadual Paulista (Unesp) &ndash; 2022<\/p><p class=\"wp-block-paragraph\">Em treinamento para uma prova de trave ol&iacute;mpica, uma atleta faz uma sa&iacute;da do aparelho, representada em quatro imagens numeradas de I a IV, em que o ponto vermelho representa o centro de <span id=\"urn:enhancement-4b3a378a-11cb-4cb9-ab02-24dfae476be0\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/massa\">massa<\/span> do corpo da atleta. A imagem I representa o instante em que a atleta perde contato com a trave, quando seu centro de <span id=\"urn:enhancement-7ac35a11-9a2a-4f8a-bd4b-8e6aaf64a6b8\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/massa\">massa<\/span> apresenta <span id=\"urn:enhancement-bfbac9fe-8746-4072-b307-b4e228df2c34\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span> horizontal v&#8320;. A imagem IV representa o instante em que ela toca o solo.<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/BSjoiQT6dGBsiU9shPbHr9ZjuWMQ_Fo153wPmJa8HXUzZpgjzEC_AngqPXQXlYJ-uEd-YKp1Mn4_t2gSrsqKPEExbJ8Mt_JP7qcG0CUQvp8PUPLkitYjsMwr9KGWeyS6I-3k5Z1ynG3xsKNK31FgiuY\" alt=\"\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\"><em>(https:\/\/docplayer.com.br. Adaptado.)<\/em><\/p><p class=\"wp-block-paragraph\">Considerando que nesse movimento somente a <span id=\"urn:enhancement-6d9788fd-c9a7-4753-9375-9e8b944bb9fb\" class=\"textannotation disambiguated wl-creative-work\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/forca\">for&ccedil;a<\/span> peso atua sobre a atleta e adotando g = 10 <span id=\"urn:enhancement-d7339fd9-5ee3-48ee-81e6-a50760d82d6f\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/metro-por-segundo\">m\/s<\/span>&sup2;, o valor de v&#8320; &eacute;<\/p><p class=\"wp-block-paragraph\"><strong>A) <\/strong>6,0 <span id=\"urn:enhancement-f70cb281-64c8-4c6e-95f7-9a7214d7c1ff\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/metro-por-segundo\">m\/s<\/span>.<br><strong>B) <\/strong>3,0 <span id=\"urn:enhancement-0e372caf-067f-4f34-8184-c417d1e2174d\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/metro-por-segundo\">m\/s<\/span>.<br><strong>C) <\/strong>5,0 <span id=\"urn:enhancement-004ff7e7-0b80-49d3-a5d4-4434f6410956\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/metro-por-segundo\">m\/s<\/span>.<br><strong>D) <\/strong>2,0 <span id=\"urn:enhancement-6dd4949e-74fe-4f69-a5ff-950d9ff86544\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/metro-por-segundo\">m\/s<\/span>.<br><strong>E) <\/strong>4,0 <span id=\"urn:enhancement-b8ef2310-9037-478d-afb9-fe8c92147a99\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/metro-por-segundo\">m\/s<\/span>.<\/p><p class=\"wp-block-paragraph\"><strong>Resposta <\/strong>Como vimos, quando um objeto &eacute; lan&ccedil;ado com uma <span id=\"urn:enhancement-2d987413-a095-4cf6-a902-d8fc1ba464bd\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span> inicial que &eacute; horizontal, sem qualquer tipo de interfer&ecirc;ncia do ar, ele continua avan&ccedil;ando horizontalmente com esta mesma <span id=\"urn:enhancement-e4a129e4-731d-45ae-92e2-d1e472dc1250\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span> ao mesmo tempo que cai, em queda livre, verticalmente, como se n&atilde;o tivesse sido jogado para o lado. Ou seja, o fato dele avan&ccedil;ar em <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/movimento-retilineo-uniforme\/\">MRU<\/a>, horizontalmente, nada interfere no fato dele cair sob a a&ccedil;&atilde;o da <span id=\"urn:enhancement-b21891f0-9f81-4bf2-864c-ba1ecf21408c\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/gravidade\">gravidade<\/span>, em um <span id=\"urn:enhancement-a4c9b7b9-f979-46fb-9b20-9aab7020dd6f\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/muv\">MUV<\/span>.<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/7LLui_t_a2BMds6VnbVRYHfVU1Uy2YM0tiFqPo1Sf9ICQoR-_k379ggQrz7zSIEuXpas4mXhXjirWHg3uidF3TXjFgxiqUCfKRpj83HIHpioJthQC-5z_70HRq-oQVnu2Qzr80kzowDhYuq--KPe0I0\" alt=\"\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">Enquanto o centro de <span id=\"urn:enhancement-26620743-6c28-4502-bfa5-1b9cac70d6c7\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/massa\">massa<\/span> da atleta cai, verticalmente, a uma altura de 0,8m (1,8 &ndash; 1,0), ela avan&ccedil;a 2m horizontalmente. Com essas informa&ccedil;&otilde;es, &eacute; poss&iacute;vel calcular o tempo de queda:<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/gQWDuCvYqXoIPJk1qs67f2veZC1_uc_zrfMJG_RcvoHQtNzVpH3oFEyBGZ-Iyia7cOnD2ZrGiKD5tb3CP_B1QjJ3bfP02JFbIA1u8prfkhePwf26fD98n68RldCewVUQsrDXwZ8OhJ93qiqJfwUgwFw\" alt=\"\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">O tempo de queda &eacute; o mesmo tempo que o centro de <span id=\"urn:enhancement-260531c2-f2aa-4ff5-ba5c-24c04393fc4d\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/massa\">massa<\/span> da atleta avan&ccedil;ou horizontalmente por 2m. Portanto, a <span id=\"urn:enhancement-f1014f88-4956-4ee6-85c4-ad157bcb62b8\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/velocidade\">velocidade<\/span> inicial depende da rela&ccedil;&atilde;o entre espa&ccedil;o deslocado, tempo de deslocamento:&nbsp;<\/p><p class=\"wp-block-paragraph\">&#8710;x = V&#8320; &sdot; t<\/p><p class=\"wp-block-paragraph\">2 = V&#8320; &sdot; 0,4<\/p><p class=\"wp-block-paragraph\">V&#8320; = 2 \/ 0,4 = 5 <span id=\"urn:enhancement-c3afefe9-1528-4ca2-bed4-0f74272032d5\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/metro-por-segundo\">m\/s<\/span><\/p><p class=\"wp-block-paragraph\"><strong>Alternativa correta: <\/strong>C.<\/p><h2 class=\"wp-block-heading\" id=\"h-estude-para-as-provas-com-a-coruja\"><span class=\"ez-toc-section\" id=\"Estude-para-as-provas-com-a-Coruja\"><\/span>Estude para as provas com a Coruja!<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Nos pacotes do Estrat&eacute;gia Vestibulares, voc&ecirc; pode acessar trilhas estrat&eacute;gias, elas s&atilde;o compostas por cronogramas completos para te guiar sobre o que, como e quando estudar. Al&eacute;m disso, os Livros Digitais Interativos (LDI) te ajudam durante todo o processo de aprendizagem, voc&ecirc; ler, grifar e anotar e, quando precisar revisar, todas as informa&ccedil;&otilde;es estar&atilde;o dispon&iacute;veis.<\/p><p class=\"wp-block-paragraph\">A Coruja te proporciona tudo isso associado com aulas did&aacute;ticas, que te d&atilde;o a base de conhecimento necess&aacute;rio em todas as disciplinas. Clique no banner e saiba mais!<\/p><p class=\"wp-block-paragraph\"><a id=\"cta\" class=\"cta-imagem\" href=\"https:\/\/vestibulares.estrategia.com\/cursos\/\" target=\"blank\">\n                <img decoding=\"async\" width=\"100%\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2021\/12\/EV1.jpg\" alt=\"CTA - Estrat\u00e9gia Vestibulares 1\" title=\"CTA - Estrat\u00e9gia Vestibulares 1\">\n        <\/a>\n\n\n\n\n<\/p><\/p>\n","protected":false},"excerpt":{"rendered":"O lan&ccedil;amento horizontal de um objeto acontece quando ele &eacute; liberado na dire&ccedil;&atilde;o horizontal a uma determinada dist&acirc;ncia&hellip;\n","protected":false},"author":23,"featured_media":114800,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[28],"tags":[],"class_list":["post-114808","post","type-post","status-publish","format-standard","has-post-thumbnail","category-fisica"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v25.9 (Yoast SEO v28.2) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Lan\u00e7amento horizontal: conceito, f\u00f3rmulas e quest\u00f5es<\/title>\n<meta name=\"description\" content=\"O lan\u00e7amento horizontal une um movimento acelerado, em queda livre, e um movimento de velocidade constante. 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