{"id":141533,"date":"2025-06-30T10:13:10","date_gmt":"2025-06-30T13:13:10","guid":{"rendered":"https:\/\/vestibulares.estrategia.com\/portal\/?p=141533"},"modified":"2025-09-16T13:43:15","modified_gmt":"2025-09-16T16:43:15","slug":"mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem","status":"publish","type":"post","link":"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/","title":{"rendered":"Mistura de solu\u00e7\u00f5es de solutos diferentes que n\u00e3o reagem"},"content":{"rendered":"<p class=\"wp-block-paragraph\">Entender a <span id=\"urn:local-annotation-298\" class=\"textannotation disambiguated\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mistura-de-solucoes\">mistura de solu&ccedil;&otilde;es<\/span> com <span id=\"urn:enhancement-ea9565e4-ac3a-47ff-a1d6-fe74e90c876c\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">solutos<\/span> diferentes que n&atilde;o reagem &eacute; essencial para o dom&iacute;nio da <span id=\"urn:enhancement-78baa20a-abbf-422d-88c1-e8bb29e4b439\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/quimica\">qu&iacute;mica<\/span> de solu&ccedil;&otilde;es. Tema fundamental para &aacute;reas como <span id=\"urn:enhancement-eeca84e6-c325-4233-baea-72e68b158df7\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/saude\">sa&uacute;de<\/span>, <span id=\"urn:enhancement-1e04b7fa-4361-4885-b409-5d243f1471a9\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/meio-ambiente\">meio ambiente<\/span> e ind&uacute;stria e que permite prever corretamente as propriedades da <span id=\"urn:enhancement-e290d90a-97a6-4b71-ba5c-a8ae7d8e9577\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> final.<p class=\"wp-block-paragraph\">A principal caracter&iacute;stica desse tipo de mistura &eacute; que cada <span id=\"urn:enhancement-17fd5fae-8964-4e3f-a956-312fac54df8d\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">soluto<\/span> mant&eacute;m sua identidade <span id=\"urn:enhancement-1ecfb203-1588-458b-8a56-8e6fe961c876\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/quimica\">qu&iacute;mica<\/span>, sem intera&ccedil;&otilde;es entre si. As quantidades (em massa ou mols) s&atilde;o conservadas, e os c&aacute;lculos de concentra&ccedil;&atilde;o seguem regras simples, por&eacute;m espec&iacute;ficas.<\/p><p class=\"wp-block-paragraph\">Neste texto, voc&ecirc; vai aprender como calcular a concentra&ccedil;&atilde;o final de cada <span id=\"urn:enhancement-6e2f465d-2bbc-4f3c-ba55-1bef52a7039d\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">soluto<\/span> em misturas sem rea&ccedil;&atilde;o qu&iacute;mica, como lidar com unidades diferentes e aplicar o conceito em contextos pr&aacute;ticos. Acompanhe abaixo.<\/p><div id=\"ez-toc-container\" class=\"ez-toc-v2_0_86 counter-hierarchy ez-toc-counter ez-toc-transparent ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\"><p class=\"ez-toc-title\" style=\"cursor:inherit\">Navegue pelo conte\u00fado<\/p>\n<\/div><nav><ul class='ez-toc-list ez-toc-list-level-1 ' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#O-novo-cenario-da-mistura\" >O novo cen&aacute;rio da mistura<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#O-principio-por-tras-do-calculo\" >O princ&iacute;pio por tr&aacute;s do c&aacute;lculo<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#Como-calcular-a-concentracao-final-de-cada-soluto\" >Como calcular a concentra&ccedil;&atilde;o final de cada soluto<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#Passo-a-passo-para-resolver-questoes\" >Passo a passo para resolver quest&otilde;es<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#Concentracao-total-de-substancias-dissolvidas\" >Concentra&ccedil;&atilde;o total de subst&acirc;ncias dissolvidas<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#Aplicacoes-praticas\" >Aplica&ccedil;&otilde;es pr&aacute;ticas<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#Questao-do-Vestibular\" >Quest&atilde;o do Vestibular<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-solutos-diferentes-que-nao-reagem\/#Se-prepare-para-o-vestibular-com-o-Estrategia\" >Se prepare para o vestibular com o Estrat&eacute;gia!<\/a><\/li><\/ul><\/nav><\/div>\n<h2 class=\"wp-block-heading\" id=\"h-o-novo-cenario-da-mistura\"><span class=\"ez-toc-section\" id=\"O-novo-cenario-da-mistura\"><\/span>O novo cen&aacute;rio da mistura<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">O primeiro ponto a ter em mente, neste caso, &eacute; que as solu&ccedil;&otilde;es misturadas cont&ecirc;m <span id=\"urn:enhancement-d0bde53c-c7e7-4b6c-9fea-096f026a1ad1\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/substancia\">subst&acirc;ncias<\/span> diferentes dissolvidas. Um exemplo cl&aacute;ssico seria misturar uma <span id=\"urn:enhancement-ed0fb3ae-db0a-4088-b779-47aeec53f8f3\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> de cloreto de s&oacute;dio (NaCl) com uma <span id=\"urn:enhancement-e5011bee-5667-4d43-b3b6-34c6d6fc1402\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> de sacarose (C&#8321;&#8322;H&#8322;&#8322;O&#8321;&#8321;).<\/p><p class=\"wp-block-paragraph\">Apesar da mistura, os <span id=\"urn:enhancement-5e6662ce-b465-4cdc-882b-a6b28124a459\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">solutos<\/span> n&atilde;o reagem entre si. Diante disso, n&atilde;o formam produtos diferentes, n&atilde;o se decomp&otilde;em nem provocam mudan&ccedil;as qu&iacute;micas uns nos outros. Logo, n&atilde;o ocorre precipita&ccedil;&atilde;o, forma&ccedil;&atilde;o de g&aacute;s, varia&ccedil;&atilde;o de cor ou libera&ccedil;&atilde;o de calor.<\/p><p class=\"wp-block-paragraph\">A mistura &eacute; puramente f&iacute;sica, e pode ser interpretada como um processo de <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/diluicao-de-solucoes-conceitos-calculos-e-aplicacoes\/\" target=\"_blank\">dilui&ccedil;&atilde;o<\/a>. Assim, existir&aacute; a conviv&ecirc;ncia das <span id=\"urn:enhancement-d2524a89-27a2-47fd-b00a-2b9dfa18d5d6\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/substancia\">subst&acirc;ncias<\/span> no mesmo solvente (geralmente a &aacute;gua).<\/p><h2 class=\"wp-block-heading\" id=\"h-o-principio-por-tras-do-calculo\"><span class=\"ez-toc-section\" id=\"O-principio-por-tras-do-calculo\"><\/span>O princ&iacute;pio por tr&aacute;s do c&aacute;lculo<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Como n&atilde;o h&aacute; rea&ccedil;&atilde;o qu&iacute;mica, cada <span id=\"urn:enhancement-809c2daf-cb05-4ea6-9914-5d3645dde8d1\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">soluto<\/span> se comporta como se estivesse sozinho na <span id=\"urn:enhancement-142a6702-c77a-42ab-a18f-7632d330b2e2\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span>. A quantidade de cada <span id=\"urn:enhancement-3d113d43-8f1f-4824-b70e-be5b43c10fe3\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/substancia\">subst&acirc;ncia<\/span> dissolvida n&atilde;o muda ap&oacute;s a mistura. Assim, a massa (em gramas) ou o n&uacute;mero de mols de cada <span id=\"urn:enhancement-b1c4bcee-ac9d-456a-8319-dd3e0508dfd3\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">soluto<\/span> permanece igual ao que havia inicialmente.<\/p><p class=\"wp-block-paragraph\">Apesar disso, existe altera&ccedil;&atilde;o no volume que, por conven&ccedil;&atilde;o, &eacute; a soma dos volumes das solu&ccedil;&otilde;es misturadas. Dessa forma, assume-se que os volumes s&atilde;o aditivos (ou seja, n&atilde;o h&aacute; contra&ccedil;&atilde;o significativa ao misturar os l&iacute;quidos).<\/p><h2 class=\"wp-block-heading\" id=\"h-como-calcular-a-concentracao-final-de-cada-soluto\"><span class=\"ez-toc-section\" id=\"Como-calcular-a-concentracao-final-de-cada-soluto\"><\/span>Como calcular a concentra&ccedil;&atilde;o final de cada soluto<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Para cada <span id=\"urn:enhancement-30f28b3a-93e0-44af-8e1d-a539b2ecaa50\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">soluto<\/span> presente na mistura, os c&aacute;lculos devem ser feitos de forma independente, seguindo o mesmo racioc&iacute;nio.<\/p><h3 class=\"wp-block-heading\" id=\"h-a-concentracao-em-massa-g-l\">A) Concentra&ccedil;&atilde;o em massa (g\/L)<\/h3><p class=\"wp-block-paragraph\">Para o <span id=\"urn:enhancement-58b96de6-48e9-4f5e-a6db-fec355b4001f\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">Soluto<\/span> A:<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"193\" height=\"68\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXddfTkRsOtwx5e8NIAvY4zPY6tCoOIHQJpUccIUcjxhdKGaI90KakBWwGIf1XPxVDGTLZEnnXVDhUtICGnNykx6BYnMHeLS-PQixkofDgTQN7KUg2GGZXavBu6ZLtNXZ0KLLVX_FA.png\" alt=\"\" class=\"wp-image-141546\" style=\"width:173px;height:auto\"><\/figure>\n<\/div><ul class=\"wp-block-list\">\n<li>Onde m<sub>A,inicial <\/sub>&eacute; a massa total do Soluto A nas solu&ccedil;&otilde;es misturadas;<\/li>\n\n\n\n<li>E V<sub>total <\/sub>&#8203; &eacute; o volume final da mistura.<\/li>\n<\/ul><p class=\"wp-block-paragraph\">A massa m<sub>A,inicial <\/sub>&#8203; pode ser calculada usando a concentra&ccedil;&atilde;o inicial da <span id=\"urn:enhancement-26e3a2f8-3af4-4cb1-917a-1ea05881a7b3\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> que cont&eacute;m A:<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"106\" height=\"42\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXdpE9XWEm488PlBnt_ra4eea4E8UfQg6oSKv8A1IssitmkdU-6XoEHAkplj7aifSDroK1xdXJPdBLNADCcj27cNqm7KbYbMrFfdkrMWUElw16blO6qQ3hQPu57oIfdlGJRHfeVVSQ.png\" alt=\"\" class=\"wp-image-141542\" style=\"width:90px;height:auto\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">Obs.: Utilize unidades compat&iacute;veis: g\/L e L.<\/p><h3 class=\"wp-block-heading\" id=\"h-b-concentracao-molar-mol-l\">B) Concentra&ccedil;&atilde;o molar (mol\/L)<\/h3><p class=\"wp-block-paragraph\">Para o mesmo <span id=\"urn:enhancement-a6378f73-26a7-4d9a-91e4-fa1cf2f6bfdd\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">Soluto<\/span> A, se quisermos a <span id=\"urn:enhancement-832fba76-16de-441c-8b06-60268910469d\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/molaridade\">concentra&ccedil;&atilde;o molar<\/span>:<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"198\" height=\"68\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXcinJHWUmcspKsGeD5dqWJk85IIMfPaS5OHzywRb1bRsu_QYBgPGoZwkoQdIGgXuiLLg-3B3Ov9A9gh6pgUTGiYwYlZXsOfRVDV68-b8ct5XYd7Si6bnsN0BFApg62uXcuo1icY4A.png\" alt=\"\" class=\"wp-image-141543\" style=\"width:176px;height:auto\"><\/figure>\n<\/div><ul class=\"wp-block-list\">\n<li>Onde n<sub>A,inicial <\/sub>&eacute; o n&uacute;mero de mols do soluto A somado das solu&ccedil;&otilde;es misturadas.<\/li>\n<\/ul><p class=\"wp-block-paragraph\">O n&uacute;mero de mols tamb&eacute;m vem da multiplica&ccedil;&atilde;o da <span id=\"urn:enhancement-be60f537-3982-4e28-a931-d231da382182\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/molaridade\">molaridade<\/span> pela quantidade de <span id=\"urn:enhancement-a2828eb4-5d12-42c2-a614-d341fa248860\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span>:<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"100\" height=\"42\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXf9GHOb0S7SgRvAkzYalOQawdZhr0QiubUkmmnU7I7QDGsKRLHDEUJPZ4Kh4pB0Qxi5TRXPWiCa2VE1x7Yr-GV3IoYS1hQmshmcShf5v9IHoRA-LhE1XRVDgV9Vi7ZTpg8-pHcIuw.png\" alt=\"\" class=\"wp-image-141539\" style=\"width:90px;height:auto\"><\/figure>\n<\/div><h3 class=\"wp-block-heading\" id=\"h-volume-total-da-mistura\">Volume total da mistura<\/h3><p class=\"wp-block-paragraph\">Para obter o volume total da mistura basta somar os volumes de todas as solu&ccedil;&otilde;es utilizadas.<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"265\" height=\"42\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXcVi3bu3aoddxM_5JE53w2C0NjVqqrcHMOCYKFUsjI8hqBTjQy2Y6mhl3TNQ9Vha-Broaj8MgvMRA045hP0faJcsID8w_KlJv1hmCnWtftWslkPcjHwQ5eWATwcqheH9NqHnt7E.png\" alt=\"\" class=\"wp-image-141545\" style=\"width:233px;height:auto\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">Obs.: Todas as medidas devem estar na mesma unidade (geralmente em litros).<\/p><h2 class=\"wp-block-heading\" id=\"h-passo-a-passo-para-resolver-questoes\"><span class=\"ez-toc-section\" id=\"Passo-a-passo-para-resolver-questoes\"><\/span>Passo a passo para resolver quest&otilde;es<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">O processo para a resolu&ccedil;&atilde;o de quest&otilde;es desse tipo pode ser esquematizado em 4 passos:<\/p><ul class=\"wp-block-list\">\n<li><strong>Passo 1:<\/strong> Identifique os solutos presentes nas solu&ccedil;&otilde;es misturadas;<\/li>\n\n\n\n<li><strong>Passo 2:<\/strong> Para cada soluto, calcule a massa (em g) ou o n&uacute;mero de mols (mol) presente em sua(s) solu&ccedil;&atilde;o(&otilde;es);<\/li>\n\n\n\n<li><strong>Passo 3:<\/strong> Some os volumes das solu&ccedil;&otilde;es misturadas para obter o V<sub>total<\/sub>; e<\/li>\n\n\n\n<li><strong>Passo 4:<\/strong> Divida a quantidade total de cada soluto por V<sub>total<\/sub> para achar a concentra&ccedil;&atilde;o final (em g\/L ou mol\/L).<\/li>\n<\/ul><p class=\"wp-block-paragraph\"><strong>Exemplo: <\/strong>considere a mistura de uma <span id=\"urn:enhancement-2b60e38d-635b-4929-9404-4bf48b43afb7\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> de NaCl 2,0 <span id=\"urn:enhancement-be42c312-2155-4715-ac7e-f4fb1e027c91\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span>\/L (100 mL), representando um sal comum, com uma <span id=\"urn:enhancement-91dce918-9566-4956-9c69-4d69d5321f41\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> de <span id=\"urn:enhancement-c9d72389-6c3a-4d0a-9bcd-ebb800ac4438\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/glicose\">glicose<\/span> (C&#8326;H&#8321;&#8322;O&#8326;) 1,0 <span id=\"urn:enhancement-4701b6af-53b8-4a10-b658-ee80ca27eb15\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span>\/L (200 mL), um a&ccedil;&uacute;car amplamente utilizado em <span id=\"urn:enhancement-3c321805-b6bc-4fbc-b7cb-2ec3f5564947\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/meio-ambiente\">meio<\/span> biol&oacute;gico.<\/p><p class=\"wp-block-paragraph\"><strong>Passo 1 &ndash;<\/strong> Identifica&ccedil;&atilde;o dos <span id=\"urn:enhancement-54a42248-7888-4db9-877c-1ef81b995b3f\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">solutos<\/span><\/p><ul class=\"wp-block-list\">\n<li>Solu&ccedil;&atilde;o 1: NaCl;<\/li>\n\n\n\n<li>Solu&ccedil;&atilde;o 2: Glicose<\/li>\n<\/ul><p class=\"wp-block-paragraph\"><strong>Passo 2<\/strong> &ndash; Calcular os mols de cada <span id=\"urn:enhancement-dc749ad6-b38b-4d02-a5d9-4cd4f4b07738\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">soluto<\/span>.<\/p><ul class=\"wp-block-list\">\n<li>NaCl: n = 2,0 &sdot; 0,1 = 0,2&thinsp;mol<\/li>\n\n\n\n<li>Glicose: n = 1,0 &sdot; 0,2 = 0,2&thinsp;mol<\/li>\n<\/ul><p class=\"wp-block-paragraph\"><strong>Passo 3<\/strong> &ndash; Somar os volumes.<\/p><p class=\"wp-block-paragraph\">V<sub>total<\/sub>=100&thinsp;mL+ 200&thinsp;mL= 300&thinsp;mL= 0,3&thinsp;L<\/p><p class=\"wp-block-paragraph\"><strong>Passo 4<\/strong> &ndash; Calcular as molaridades finais.<\/p><ul class=\"wp-block-list\">\n<li>NaCl<\/li>\n<\/ul><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"223\" height=\"57\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXfuml4UOM46rm3XWsEOla0K7szh_eGmGaW4G2Y0UoFy7JujwePIiOLjZ2EyDRT6-N-l6vXzH36FVrBZugCfsWfvs-zbdKLS30WZHiIZKMY6zbLYPmumXHRjba_vnVzvj3lP-L0bSg.png\" alt=\"\" class=\"wp-image-141544\" style=\"width:193px;height:auto\"><\/figure>\n<\/div><ul class=\"wp-block-list\">\n<li>Glicose<\/li>\n<\/ul><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"223\" height=\"57\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXetUb_z6iZBMMZ9lpKIUJ1TimQWF-zcdBIDgw30Mf9sBW0zsYih8PeUhxu0MAPrd_ArpKjmuva9IqCR4NTS0v41U8B8cTncXIQ9JYhf12_J3OPdp_yHEkhaeW-RQGdjOnsLK_v9eg.png\" alt=\"\" class=\"wp-image-141540\" style=\"width:201px;height:auto\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">Assim, na <span id=\"urn:enhancement-5b1b95b9-73be-4508-883e-cae045e10557\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> final temos:<\/p><ul class=\"wp-block-list\">\n<li><strong>[Na&#8314;] = 0,67 mol\/L<\/strong><\/li>\n\n\n\n<li><strong>[Cl&#8315;] = 0,67 mol\/L<\/strong><\/li>\n\n\n\n<li><strong>[Glicose] = 0,67 mol\/L<\/strong><\/li>\n<\/ul><p class=\"wp-block-paragraph\">Obs.: Se as solu&ccedil;&otilde;es misturadas tiverem unidades diferentes, &eacute; necess&aacute;rio unific&aacute;-las para que os c&aacute;lculos fa&ccedil;am sentido. Por exemplo:<\/p><ul class=\"wp-block-list\">\n<li>Se uma solu&ccedil;&atilde;o est&aacute; em mol\/L e voc&ecirc; quer a concentra&ccedil;&atilde;o final em g\/L, converta os mols em gramas (usando a massa molar do soluto).<\/li>\n\n\n\n<li>Se estiver em % m\/v, converta para g\/L sabendo que 1% m\/v = 1 g de soluto em 100 mL = 10 g\/L.<\/li>\n<\/ul><figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<div class=\"cs-embed cs-embed-responsive\"><iframe title=\"Dilui&ccedil;&atilde;o, Mistura de Solu&ccedil;&otilde;es Que N&atilde;o Reagem e Mistura de Solu&ccedil;&otilde;es Que Reagem -Prof. Guilherme Alves\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/Kxw6CO47gds?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe><\/div>\n<\/div><\/figure><h2 class=\"wp-block-heading\" id=\"h-concentracao-total-de-substancias-dissolvidas\"><span class=\"ez-toc-section\" id=\"Concentracao-total-de-substancias-dissolvidas\"><\/span>Concentra&ccedil;&atilde;o total de subst&acirc;ncias dissolvidas<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Al&eacute;m das concentra&ccedil;&otilde;es individuais, &agrave;s vezes &eacute; necess&aacute;rio saber a concentra&ccedil;&atilde;o total de <span id=\"urn:enhancement-caa8c80c-11a1-40c8-a386-90bdfe895047\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/substancia\">subst&acirc;ncias<\/span> dissolvidas. A partir disso &eacute; poss&iacute;vel prever <span id=\"urn:enhancement-9102e9f8-34a0-4a29-9304-0f997cfea4bf\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/propriedades-coligativas\">propriedades coligativas<\/span> como press&atilde;o osm&oacute;tica ou ponto de ebuli&ccedil;&atilde;o.<\/p><p class=\"wp-block-paragraph\">Essa concentra&ccedil;&atilde;o pode ser expressa como:<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"332\" height=\"42\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXddC4puLOKynD8IqxvQhd_oj0zJrtV88_yY9WelNIppS9uUd0RAak_0U8LEE7DQy2qQo8rW1o5-5YO1BG2R9aDmKLmtG14F5TslMpU4HkJXgcTrrboGJxqvKWiyvzmKLujI6OrkHw.png\" alt=\"\" class=\"wp-image-141547\" style=\"width:294px;height:auto\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">Ou, se estivermos tratando de <span id=\"urn:enhancement-bb37d1eb-0ebd-4ed1-a3bd-9a893fd92782\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/molaridade\">molaridade<\/span>:<\/p><div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"350\" height=\"42\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/06\/AD_4nXdxuoAGDb_1_OQ25BXhFZmk4VaW0ho2R36usbpiA_mHAoIJN4wqjUHjhp8_d4URsgF3eoKmfobslKPrwbzMBJKW2rwIcEHwRqQqocwL4VASTD0nedlrxoarjAjAZdxn2Cz7enslsg.png\" alt=\"\" class=\"wp-image-141541\" style=\"width:310px;height:auto\"><\/figure>\n<\/div><p class=\"wp-block-paragraph\">Isso representa a quantidade total de part&iacute;culas dissolvidas por litro de <span id=\"urn:enhancement-e2e8534b-82aa-462c-b7c0-20958616968e\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> &mdash; &uacute;til em contextos f&iacute;sicos e biol&oacute;gicos.<\/p><p class=\"wp-block-paragraph\">+ Veja tamb&eacute;m: <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/materias\/quimica\/mistura-de-solucoes-de-mesmo-soluto-formulas-e-definicao\/\" target=\"_blank\">Mistura de solu&ccedil;&otilde;es de mesmo soluto: f&oacute;rmulas e defini&ccedil;&atilde;o<\/a><\/p><h2 class=\"wp-block-heading\" id=\"h-aplicacoes-praticas\"><span class=\"ez-toc-section\" id=\"Aplicacoes-praticas\"><\/span>Aplica&ccedil;&otilde;es pr&aacute;ticas<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">A mistura de solu&ccedil;&otilde;es e os c&aacute;lculos apresentados s&atilde;o amplamente utilizados em diversos contextos como:<\/p><ul class=\"wp-block-list\">\n<li><strong>Preparos laboratoriais<\/strong>: como meios de cultura, onde diferentes nutrientes s&atilde;o dissolvidos separadamente e misturados sem intera&ccedil;&atilde;o qu&iacute;mica entre eles.<\/li>\n\n\n\n<li><strong>Farm&aacute;cia e ind&uacute;stria<\/strong>: como na formula&ccedil;&atilde;o de xaropes ou solu&ccedil;&otilde;es contendo m&uacute;ltiplos f&aacute;rmacos ativos que n&atilde;o reagem entre si.<\/li>\n\n\n\n<li><strong>Alimentos e bebidas<\/strong>: como refrigerantes com a&ccedil;&uacute;car, sais minerais e outros componentes dissolvidos.<\/li>\n<\/ul><h2 class=\"wp-block-heading\" id=\"h-questao-do-vestibular\"><span class=\"ez-toc-section\" id=\"Questao-do-Vestibular\"><\/span>Quest&atilde;o do Vestibular<span class=\"ez-toc-section-end\"><\/span><\/h2><h3 class=\"wp-block-heading\" id=\"h-ufrgs-2020\">UFRGS (2020)<\/h3><p class=\"wp-block-paragraph\">Uma <span id=\"urn:enhancement-f077d57a-b000-41bf-88ca-4605372699ce\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> &eacute; preparada misturando-se 40,00 mL de NaOH de concentra&ccedil;&atilde;o 0,30 <span id=\"urn:enhancement-457e3a2d-e439-4991-8f16-8ff179b45bf9\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> L&#8315;&sup1; e 60,00 mL de KOH 0,20 <span id=\"urn:enhancement-b29c205d-2bd7-481d-b4b3-873002303f97\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> L&#8315;&sup1;.&nbsp; As concentra&ccedil;&otilde;es molares de <span id=\"urn:enhancement-0970f31e-afe1-44f5-b5a4-c969c273341a\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/ions\">&iacute;ons<\/span> Na&#8314;, K&#8314; e <span id=\"urn:enhancement-bfdb8b1f-6f57-4500-8e41-bf84fef86016\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/hidroxila\">OH<\/span>&#8315; na <span id=\"urn:enhancement-bf3ccfc9-a8e7-41fa-847b-0a1c8165a06c\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/solucao\">solu&ccedil;&atilde;o<\/span> resultante ser&atilde;o, em <span id=\"urn:enhancement-261311cc-d229-4ef5-8ab4-042d2e05390c\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> L&#8315;&sup1;, respectivamente,<\/p><p class=\"wp-block-paragraph\"><strong>A)<\/strong> 0,012; 0,012 e 0,024.<br><strong>B) <\/strong>0,04; 0,06 e 0,10.<br><strong>C) <\/strong>0,12; 0,12 e 0,12.<br><strong>D) <\/strong>0,12; 0,12 e 0,24.<br><strong>E) <\/strong>0,30; 0,20 e 0,50.<\/p><details class=\"wp-block-details is-layout-flow wp-block-details-is-layout-flow\"><summary><strong>Alternativa correta:<\/strong><\/summary>\n<p class=\"wp-block-paragraph\"><strong>D<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Resolu&ccedil;&atilde;o:&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Passo 1:<strong> <\/strong>Identifica&ccedil;&atilde;o dos <span id=\"urn:enhancement-6b697f91-0d48-45ad-bf61-f0f38bf84476\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">solutos<\/span><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>NaOH: 40,00 mL = 0,040 L, concentra&ccedil;&atilde;o = 0,30 mol\/L<\/li>\n\n\n\n<li>KOH: 60,00 mL = 0,060 L, concentra&ccedil;&atilde;o = 0,20 mol\/L<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Passo 2: Calcular os mols de cada <span id=\"urn:enhancement-ac93c2df-31ef-4195-957f-3b4ae9f32e23\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/soluto\">soluto<\/span><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>NaOH:<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">n = C&sdot;V = 0,30 &sdot; 0,040 = 0,012&thinsp;<span id=\"urn:enhancement-34564db7-2320-422a-99b6-76ae3fee776e\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> de NaOH &rArr; 0,012&thinsp;<span id=\"urn:enhancement-1c9535b5-3557-43ad-bef0-9faa091ca328\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> de Na&#8314; e 0,012 <span id=\"urn:enhancement-ec4aa413-d55b-4a94-b5f0-742cc8931f3d\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> de <span id=\"urn:enhancement-0edf8ee3-7457-4a26-bb80-2ca8e58bc6e5\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/hidroxila\">OH<\/span>&#8315;<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>KOH:<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">n = C&sdot;V = 0,20 &sdot; 0,060 = 0,012&thinsp;<span id=\"urn:enhancement-d43da137-3684-4e63-a332-e45e416fc99b\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> de KOH&rArr;0,012&thinsp;<span id=\"urn:enhancement-65b2a7a5-9d77-4390-bb35-a4aa7094ed5c\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> de K&#8314; e 0,012 <span id=\"urn:enhancement-9e7442eb-d5af-4b81-a975-39103e31530e\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> de <span id=\"urn:enhancement-2cfd23b4-16aa-456c-adfb-e9019c131123\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/hidroxila\">OH<\/span>&#8315;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Passo 3: Somar os volumes<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vtotal=40,00&thinsp;mL+60,00&thinsp;mL=100,00&thinsp;mL=0,100&thinsp;L<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Passo 4: Calcular as concentra&ccedil;&otilde;es finais<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[OH&#8315;] = 0,012&thinsp;(de NaOH) + 0,012&thinsp;(de KOH) = 0,024&thinsp;<span id=\"urn:enhancement-89bcf20d-0f19-40cb-ab6d-50f523396e74\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span> &rArr; 0,024 \/ 0,100= 0,24&thinsp;<span id=\"urn:enhancement-5554d2a5-581f-486b-9374-fb5e215cd804\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span>\/L<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[Na&#8314;] = 0,012 \/ 0,100=0,12&thinsp;<span id=\"urn:enhancement-a2756028-2bf1-4d09-8817-091574441950\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span>\/L<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[K&#8314;] =0,012 \/ 0,100=0,12&thinsp;<span id=\"urn:enhancement-44afe086-46b4-4fc0-bdac-fbb9742d4e80\" class=\"textannotation disambiguated wl-thing\" itemid=\"https:\/\/data.wordlift.io\/wl110249\/entity\/mol\">mol<\/span>\/L<\/p>\n<\/details><h2 class=\"wp-block-heading\" id=\"h-se-prepare-para-o-vestibular-com-o-estrategia\"><span class=\"ez-toc-section\" id=\"Se-prepare-para-o-vestibular-com-o-Estrategia\"><\/span>Se prepare para o vestibular com o Estrat&eacute;gia!<span class=\"ez-toc-section-end\"><\/span><\/h2><p class=\"wp-block-paragraph\">Nos cursos preparat&oacute;rios da Coruja, os alunos s&atilde;o treinados para conectar diferentes &aacute;reas do conhecimento e aplicar essas informa&ccedil;&otilde;es em simulados e provas.<\/p><p class=\"wp-block-paragraph\">As aulas s&atilde;o ministradas por professores especialistas, com nossos Livros Digitais Interativos (LDI), al&eacute;m de contar com simulados exclusivos. 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