{"id":31787,"date":"2019-11-12T16:01:56","date_gmt":"2019-11-12T19:01:56","guid":{"rendered":"https:\/\/blog.estrategiavestibulares.com.br\/?p=31787"},"modified":"2021-12-15T16:51:21","modified_gmt":"2021-12-15T19:51:21","slug":"gabarito-ufpr-fisica","status":"publish","type":"post","link":"https:\/\/vestibulares.estrategia.com\/portal\/materias\/fisica\/gabarito-ufpr-fisica\/","title":{"rendered":"Gabarito UFPR 2020 \u2013 F\u00edsica \u2013 Resolu\u00e7\u00e3o Comentada"},"content":{"rendered":"<p>Ol&aacute;, caro aluno. Seja Bem-Vindo. Escrevo este artigo para disponibilizar a voc&ecirc; as quest&otilde;es de <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/category\/fisica\/\" target=\"_blank\">F&iacute;sica<\/a> da prova de 1&ordf; fase <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/vestibulares\/vestibular-ufpr\/\" target=\"_blank\">UFPR 2020<\/a>. Durante a leitura deste artigo, voc&ecirc; vai conferir o que cobravam as quest&otilde;es e como voc&ecirc; teria que resolver at&eacute; chegar ao Gabarito sugerido pela UFPR. Vamos nessa?<h2 class=\"wp-block-heading\" id=\"h-ufpr-2020\">UFPR 2020<\/h2><h3 class=\"wp-block-heading\" id=\"h-questao-28\"><strong>Quest&atilde;o 28<\/strong><\/h3><p>Um objeto de massa m constante est&aacute; situado no topo de um plano inclinado sem atrito, de &acirc;ngulo de inclina&ccedil;&atilde;o <em>&theta;<\/em> conforme mostra a figura ao lado. O objeto est&aacute; inicialmente em repouso, a uma altura <em>H<\/em> da base do plano inclinado, e pode ser considerado uma part&iacute;cula, tendo em conta as dimens&otilde;es envolvidas. Num dado instante, ele &eacute; solto e desce o plano inclinado, chegando &agrave; sua base num instante posterior. Durante o movimento, o objeto n&atilde;o fica sujeito a nenhum tipo de atrito e as observa&ccedil;&otilde;es s&atilde;o feitas por um referencial inercial. No local, a acelera&ccedil;&atilde;o gravitacional vale, em m&oacute;dulo, <em>g<\/em>.<\/p><figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/10\/gabarito-ufpr-f%C3%ADsica-300x134.png\" alt=\"gabarito ufpr f&iacute;sica\" class=\"wp-image-31788\" width=\"356\" height=\"159\"><\/figure><p>Levando em considera&ccedil;&atilde;o os dados apresentados, assinale a alternativa que corresponde ao valor do m&oacute;dulo da quantidade de movimento (momento linear) <em>Q<\/em> que o objeto de massa m adquire ao chegar &agrave; base do plano inclinado. <\/p><p>a) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q&amp;space;=&amp;space;m%5Csqrt%7B2gH%7D\" alt=\"\\dpi{100} \\large Q = m\\sqrt{2gH}\" align=\"absmiddle\"><\/p><p>b) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q&amp;space;=&amp;space;%5Csqrt%7B2mgH%7D\" alt=\"\\dpi{100} \\large Q = \\sqrt{2mgH}\" align=\"absmiddle\"><\/p><p>c) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q&amp;space;=&amp;space;m%5Csqrt%7B2gHtg%5Ctheta%7D\" alt=\"\\dpi{100} \\large Q = m\\sqrt{2gHtg\\theta}\" align=\"absmiddle\"><\/p><p>d) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q&amp;space;=&amp;space;m%5Csqrt%7B2gHsen%5Ctheta&amp;space;%7D\" alt=\"\\dpi{100} \\large Q = m\\sqrt{2gHsen\\theta }\" align=\"absmiddle\"><\/p><p>e) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q&amp;space;=&amp;space;%5Csqrt%7B2mgHcos%5Ctheta&amp;space;%7D\" alt=\"\\dpi{100} \\large Q = \\sqrt{2mgHcos\\theta }\" align=\"absmiddle\"><\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>Se o objeto n&atilde;o fica sujeito a nenhum tipo de atrito, temos que a energia mec&acirc;nica se conserva: <\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%E3%80%96E.M.%E3%80%97_A=%E3%80%96E.M.%E3%80%97_B\" alt=\"\\dpi{100} \\large &#12310;E.M.&#12311;_A=&#12310;E.M.&#12311;_B\" align=\"absmiddle\"><\/p><p>Conserva&ccedil;&atilde;o da energia mec&acirc;nica<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Ec_A+Epotg_A+Eel_A=Ec_B+Epotg_B+Eel_B\" alt=\"\\dpi{100} \\large Ec_A+Epotg_A+Eel_A=Ec_B+Epotg_B+Eel_B\" align=\"absmiddle\"><\/p><p>E como n&atilde;o temos energias el&aacute;sticas envolvidas no movimento entre B e A:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Ec_A+Epotg_A+%5Ccancel%7BEel_%7BA%7D%7D=Ec_B+Epotg_B+%5Ccancel%7BEel_%7BB%7D%7D\" alt=\"\\dpi{100} \\large Ec_A+Epotg_A+\\cancel{Eel_{A}}=Ec_B+Epotg_B+\\cancel{Eel_{B}}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Ec_A+Epotg_A=Ec_B+Epotg_B\" alt=\"\\dpi{100} \\large Ec_A+Epotg_A=Ec_B+Epotg_B\" align=\"absmiddle\"><\/p><p>Adotando o referencial como o ch&atilde;o, temos que a altura no ponto B &eacute; nula. A velocidade inicial do balan&ccedil;o, no ponto A, tamb&eacute;m &eacute; inexistente, desse modo:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Ccancel%7BEc_%7BA%7D%7D+Epotg_A=Ec_B+%5Ccancel%7BEpotg_%7BB%7D%7D\" alt=\"\\dpi{100} \\large \\cancel{Ec_{A}}+Epotg_A=Ec_B+\\cancel{Epotg_{B}}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Epotg_A=Ec_B\" alt=\"\\dpi{100} \\large Epotg_A=Ec_B\" align=\"absmiddle\"><\/p><p>Desenvolvendo essa equa&ccedil;&atilde;o:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;m%5Ccdot&amp;space;g%5Ccdot&amp;space;h_%7BA%7D=%5Cfrac%7Bm%5Ccdot&amp;space;(v_%7BB%7D)%5E%7B2%7D%7D%7B2%7D\" alt=\"\\dpi{100} \\large m\\cdot g\\cdot h_{A}=\\frac{m\\cdot (v_{B})^{2}}{2}\" align=\"absmiddle\"><\/p><p>Dividindo todos os termos por m:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;g%5Ccdot&amp;space;h_A=%5Cfrac%7B%5Cleft(v_B%5Cright)%5E2%7D%7B2%7D\" alt=\"\\dpi{100} \\large g\\cdot h_A=\\frac{\\left(v_B\\right)^2}{2}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Cleft(v_B%5Cright)%5E2=2%5Ccdot&amp;space;g%5Ccdot&amp;space;h_A\" alt=\"\\dpi{100} \\large \\left(v_B\\right)^2=2\\cdot g\\cdot h_A\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;v_B=%5Csqrt%7B2%5Ccdot&amp;space;g%5Ccdot&amp;space;h_A%7D\" alt=\"\\dpi{100} \\large v_B=\\sqrt{2\\cdot g\\cdot h_A}\" align=\"absmiddle\"><\/p><p>Adotando as vari&aacute;veis do problema, temos:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;v_B=%5Csqrt%7B2%5Ccdot&amp;space;g%5Ccdot&amp;space;H%7D\" alt=\"\\dpi{100} \\large v_B=\\sqrt{2\\cdot g\\cdot H}\" align=\"absmiddle\"><\/p><p>A quantidade de movimento no ponto mais baixo, por n&oacute;s chamado de ponto &ldquo;B&rdquo; &eacute; dada pelo produto entre a massa da part&iacute;cula e a sua velocidade nesse ponto, previamente calculada:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q=m%5Ccdot&amp;space;v_B\" alt=\"\\dpi{100} \\large Q=m\\cdot v_B\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q=m%5Ccdot%5Csqrt%7B2%5Ccdot&amp;space;g%5Ccdot&amp;space;H%7D\" alt=\"\\dpi{100} \\large Q=m\\cdot\\sqrt{2\\cdot g\\cdot H}\" align=\"absmiddle\"><\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: A<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-29\"><strong>Quest&atilde;o 29<\/strong><\/h3><p>Grandezas f&iacute;sicas s&atilde;o caracterizadas pelos seus valores num&eacute;ricos e respectivas unidades. H&aacute; v&aacute;rios sistemas de unidades, sendo que o principal, em uso na maioria dos pa&iacute;ses, &eacute; o Sistema Internacional de Unidades &ndash; SI. Esse sistema &eacute; composto por sete unidades b&aacute;sicas (ou fundamentais) e por unidades derivadas, formadas por combina&ccedil;&otilde;es daquelas. A respeito do assunto, considere as seguintes afirmativas:<\/p><ol class=\"wp-block-list\"><li>No SI, a unidade associada com a grandeza capacit&acirc;ncia &eacute; farad.<\/li><li>No SI, a unidade associada com a grandeza energia &eacute; erg.<\/li><li>No SI, a unidade associada com a grandeza campo magn&eacute;tico &eacute; tesla.<\/li><li>No SI, a unidade associada com a grandeza press&atilde;o &eacute; pascal.<\/li><\/ol><p>Assinale a alternativa correta.<\/p><p>a) Somente a afirmativa 1 &eacute; verdadeira.<br>b) Somente as afirmativas 1 e 2 s&atilde;o verdadeiras.<br>c) Somente as afirmativas 1, 3 e 4 s&atilde;o verdadeiras.<br>d) Somente as afirmativas 2, 3 e 4 s&atilde;o verdadeiras.<br>e) As afirmativas 1, 2, 3 e 4 s&atilde;o verdadeiras.<\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-1\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>As grandezas derivadas de nomenclatura especial mais usadas do Sistema Internacional s&atilde;o:<\/p><figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/10\/gabarito-ufpr-f%C3%ADsica2-1024x686.png\" alt=\"gabarito ufpr f&iacute;sica\" class=\"wp-image-31811\"><\/figure><p>Notamos que a &uacute;nica afirmativa incorreta &eacute; a segundo, visto que a grandeza associada &agrave; energia &eacute; o Joule [J]. <\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: C<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-30\"><strong>Quest&atilde;o 30<\/strong><\/h3><p>Um observador inercial analisa o movimento de um dado objeto de massa <em>m<\/em> constante e constr&oacute;i o gr&aacute;fico <em>v<\/em> x <em>t<\/em> mostrado ao lado, em que <em>v<\/em> &eacute; a velocidade do objeto e <em>t<\/em> &eacute; o tempo. O movimento ocorre numa linha reta. <\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/10\/gabarito-ufpr-f%C3%ADsica3-300x192.png\" alt=\"gabarito ufpr f&iacute;sica\" class=\"wp-image-31813\"><\/figure><\/div><p>Levando em considera&ccedil;&atilde;o os dados apresentados no gr&aacute;fico, assinale a alternativa que apresenta corretamente o valor do deslocamento <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;x\" alt=\"\\dpi{100} \\large \\Delta x\" align=\"absmiddle\"> do objeto entre os instantes <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;t=&amp;space;0\" alt=\"\\dpi{100} \\large t= 0\" align=\"absmiddle\"> e <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;t&amp;space;=&amp;space;5s\" alt=\"\\dpi{100} \\large t = 5s\" align=\"absmiddle\">.<\/p><p>a) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;x&amp;space;=&amp;space;5,0m\" alt=\"\\dpi{100} \\large \\Delta x = 5,0m\" align=\"absmiddle\"><\/p><p>b) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;x&amp;space;=&amp;space;7,5m\" alt=\"\\dpi{100} \\large \\Delta x = 7,5m\" align=\"absmiddle\"><\/p><p>c) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;x&amp;space;=&amp;space;10,0m\" alt=\"\\dpi{100} \\large \\Delta x = 10,0m\" align=\"absmiddle\"><\/p><p>d) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;x&amp;space;=&amp;space;12,5m\" alt=\"\\dpi{100} \\large \\Delta x = 12,5m\" align=\"absmiddle\"><\/p><p>e) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;x&amp;space;=&amp;space;15,0m\" alt=\"\\dpi{100} \\large \\Delta x = 15,0m\" align=\"absmiddle\"><\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-2\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>Em um gr&aacute;fico que relaciona a velocidade e o tempo de um m&oacute;vel, temos que a &aacute;rea abaixo da curva &eacute; numericamente igual ao deslocamento do m&oacute;vel. Podemos calcular o deslocamento entre os instantes t = 0 e t =5s pela diferen&ccedil;a entre as &aacute;reas: <\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;A_%7Bt=0%5C&amp;space;a%5C&amp;space;t=5%7D=A_%7Bt=0%5C&amp;space;a%5C&amp;space;t=10%7D-A_%7Bt=5%5C&amp;space;a%5C&amp;space;t=10%7D\" alt=\"\\dpi{100} \\large A_{t=0\\ a\\ t=5}=A_{t=0\\ a\\ t=10}-A_{t=5\\ a\\ t=10}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;A_%7Bt=0%5C&amp;space;a%5C&amp;space;t=5%7D=%5Cfrac%7B10%5Ccdot2%7D%7B2%7D-%5Cfrac%7B5%5Ccdot1%7D%7B2%7D=10-2,5=7,5\" alt=\"\\dpi{100} \\large A_{t=0\\ a\\ t=5}=\\frac{10\\cdot2}{2}-\\frac{5\\cdot1}{2}=10-2,5=7,5\" align=\"absmiddle\"><\/p><p>Dessa forma:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%E2%88%86St=0&amp;space;a&amp;space;t=5%E2%89%A1At=0&amp;space;a&amp;space;t=5\" alt=\"\\dpi{100} \\large &#8710;St=0 a t=5&equiv;At=0 a t=5\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%E2%88%86St=0&amp;space;a&amp;space;t=5=7,5&amp;space;m\" alt=\"\\dpi{100} \\large &#8710;St=0 a t=5=7,5 m\" align=\"absmiddle\"><\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: B<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-31\"><strong>Quest&atilde;o 31<\/strong><\/h3><p>A respeito de campos magn&eacute;ticos, considere as seguintes afirmativas:<\/p><ol class=\"wp-block-list\"><li>A Terra tem um campo magn&eacute;tico.<\/li><li>Correntes el&eacute;tricas produzem campos magn&eacute;ticos.<\/li><li>Quando polos de mesmo nome pertencentes a dois &iacute;m&atilde;s diferentes s&atilde;o aproximados, eles se repelem.<\/li><li>Uma carga el&eacute;trica com velocidade nula sob a a&ccedil;&atilde;o de um campo magn&eacute;tico n&atilde;o sente a a&ccedil;&atilde;o de nenhuma for&ccedil;a magn&eacute;tica.<\/li><\/ol><p>Assinale a alternativa correta.<\/p><p>a) As afirmativas 1, 2, 3 e 4 s&atilde;o verdadeiras.<br>b) Somente as afirmativas 2, 3 e 4 s&atilde;o verdadeiras.<br>c) Somente as afirmativas 1, 3 e 4 s&atilde;o verdadeiras.<br>d) Somente as afirmativas 1 e 2 s&atilde;o verdadeiras.<br>e) Somente a afirmativa 1 &eacute; verdadeira.<\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-3\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>1) Verdadeira. O planeta Terra possui um campo magn&eacute;tico:<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/10\/gabarito-ufpr-f%C3%ADsica4-300x254.png\" alt=\"gabarito ufpr f&iacute;sica\" class=\"wp-image-31815\"><\/figure><\/div><p>2) Verdadeira. Cargas em movimento, como a corrente el&eacute;trica s&atilde;o capazes de produzir campos magn&eacute;ticos.<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/10\/gabarito-ufpr-f%C3%ADsica5-300x160.png\" alt=\"gabarito ufpr f&iacute;sica\" class=\"wp-image-31816\"><\/figure><\/div><p>3) Verdadeira. A unidade associada com a grandeza campo magn&eacute;tico, no Sistema Internacional, &eacute; o Tesla:<\/p><figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/10\/gabarito-ufpr-f%C3%ADsica-21-1024x78.png\" alt=\"gabarito ufpr f&iacute;sica 2\" class=\"wp-image-31817\"><\/figure><p>4) Verdadeira. A unidade associada com a grandeza press&atilde;o, no Sistema Internacional, &eacute; o Pascal, equivalente ao Newton por metro quadrado:<\/p><figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/10\/gabarito-ufpr-f%C3%ADsica6-1024x77.png\" alt=\"gabarito ufpr f&iacute;sica\" class=\"wp-image-31818\"><\/figure><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: A<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-32\"><strong>Quest&atilde;o 32<\/strong><\/h3><p>As propriedades el&eacute;tricas de dois resistores A e B foram investigadas, e os dados obtidos para eles foram dispostos na forma de um gr&aacute;fico <em>V x i<\/em>, em que <em>V<\/em> &eacute; a tens&atilde;o aplicada e <em>i<\/em> &eacute; a corrente el&eacute;trica que por eles circula. As curvas para os resistores A (linha cheia) e B (linha tracejada) s&atilde;o apresentadas na figura ao lado.<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/11\/image21.png\" alt=\"\" class=\"wp-image-33007\"><\/figure><\/div><p>Com base nos dados apresentados, considere as seguintes afirmativas: <\/p><ol class=\"wp-block-list\"><li>O resistor B &eacute; &ocirc;hmico. <\/li><li>Os resistores t&ecirc;m resist&ecirc;ncias iguais quando submetidos a uma tens&atilde;o de <em>10V<\/em>.<\/li><li> A pot&ecirc;ncia dissipada pelo resistor A quando submetido a uma tens&atilde;o de <em>20V<\/em> vale <em>0,6W<\/em>.<\/li><li> O resistor B apresenta uma resist&ecirc;ncia de 50&Omega; quando submetido a uma tens&atilde;o de <em>5V<\/em>.<\/li><\/ol><p>Assinale a alternativa correta.<\/p><p>a) Somente a afirmativa 1 &eacute; verdadeira. <\/p><p>b) Somente as afirmativas 2 e 4 s&atilde;o verdadeiras. <\/p><p>c) Somente as afirmativas 3 e 4 s&atilde;o verdadeiras.<\/p><p>d) Somente as afirmativas 1, 2 e 3 s&atilde;o verdadeiras. <\/p><p>e) As afirmativas 1, 2, 3 e 4 s&atilde;o verdadeiras.<\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-4\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>1) Verdadeira. Em um condutor &ocirc;hmico mantido &agrave; temperatura constante, a resist&ecirc;ncia el&eacute;trica &eacute; constante. Dessa forma, se plotarmos um gr&aacute;fico da tens&atilde;o pela corrente, temos:<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/11\/image22.png\" alt=\"\" class=\"wp-image-33008\"><\/figure><\/div><p>2) Verdadeira. Isso pode ser observado pela sobreposi&ccedil;&atilde;o das curvas quando na tens&atilde;o de 10V:<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/11\/image23.png\" alt=\"\" class=\"wp-image-33009\"><\/figure><\/div><p>3) Verdadeira. De acordo com o gr&aacute;fico, o resistor A, quando submetido a uma tens&atilde;o de <em>20V<\/em>, &eacute; atravessado por uma corrente de <em>30mA<\/em>.<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/11\/image24.png\" alt=\"\" class=\"wp-image-33010\"><\/figure><\/div><p>A pot&ecirc;ncia por ele dissipada pode ser calculada por:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Pot=V%5Ccdot&amp;space;i\" alt=\"\\dpi{100} \\large Pot=V\\cdot i\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Pot=20%5Ccdot30%5Ccdot%7B10%7D%5E%7B-3%7D=2%5Ccdot3%5Ccdot%7B10%7D%5E2%5Ccdot%7B10%7D%5E%7B-3%7D=6%5Ccdot%7B10%7D%5E%7B-1%7D=0,6%5C&amp;space;W\" alt=\"\\dpi{100} \\large Pot=20\\cdot30\\cdot{10}^{-3}=2\\cdot3\\cdot{10}^2\\cdot{10}^{-3}=6\\cdot{10}^{-1}=0,6\\ W\" align=\"absmiddle\"><\/p><p>4) Falsa. De acordo com o gr&aacute;fico, o resistor B &eacute; atravessado por uma corrente de <em>10mA<\/em> quando submetido a uma tens&atilde;o de <em>5V<\/em>. Como B &eacute; um resistor &ocirc;hmico, podemos calcular a sua resist&ecirc;ncia tomando esse ou qualquer outro ponto do gr&aacute;fico fazendo uso da 1&ordf; lei de Ohm:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;V=R%5Ccdot&amp;space;i\" alt=\"\\dpi{100} \\large V=R\\cdot i\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;5=R%5Ccdot10%5Ccdot%7B10%7D%5E%7B-3%7D\" alt=\"\\dpi{100} \\large 5=R\\cdot10\\cdot{10}^{-3}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;R=%5Cfrac%7B5%7D%7B%7B10%7D%5E%7B-2%7D%7D=5%5Ccdot%7B10%7D%5E2=500%5C&amp;space;%5COmega\" alt=\"\\dpi{100} \\large R=\\frac{5}{{10}^{-2}}=5\\cdot{10}^2=500\\ \\Omega\" align=\"absmiddle\"><\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: D<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-33\"><strong>Quest&atilde;o 33<\/strong><\/h3><p>Uma onda sonora se propaga num meio em que sua velocidade, em m&oacute;dulo, vale <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;500m\/s\" alt=\"\\dpi{100} \\large 500m\/s\" align=\"absmiddle\">. Sabe-se que o per&iacute;odo dessa onda &eacute; de <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;20%5C&amp;space;%5Cmathbit%7B%5Cmu&amp;space;s%7D\" alt=\"\\dpi{100} \\large 20\\ \\mathbit{\\mu s}\" align=\"absmiddle\"> . Considerando os dados apresentados, a onda nesse meio apresenta o seguinte comprimento de onda <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;(%5Cmathbit%7B%5Clambda%7D)\" alt=\"\\dpi{100} \\large (\\mathbit{\\lambda})\" align=\"absmiddle\">:<\/p><p>a) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Clambda=250%5C&amp;space;mm\" alt=\"\\dpi{100} \\large \\lambda=250\\ mm\" align=\"absmiddle\"><\/p><p>b) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Clambda=100%5C&amp;space;mm\" alt=\"\\dpi{100} \\large \\lambda=100\\ mm\" align=\"absmiddle\"><\/p><p>c) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Clambda=25%5C&amp;space;mm\" alt=\"\\dpi{100} \\large \\lambda=25\\ mm\" align=\"absmiddle\"><\/p><p>d) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Clambda=10%5C&amp;space;mm\" alt=\"\\dpi{100} \\large \\lambda=10\\ mm\" align=\"absmiddle\"><\/p><p>e) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Clambda=1%5C&amp;space;mm\" alt=\"\\dpi{100} \\large \\lambda=1\\ mm\" align=\"absmiddle\"><\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-5\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>A frequ&ecirc;ncia de uma onda &eacute; dada pelo inverso do seu per&iacute;odo:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;f=%5Cfrac%7B1%7D%7BT%7D\" alt=\"\\dpi{100} \\large f=\\frac{1}{T}\" align=\"absmiddle\"><\/p><p>Pela equa&ccedil;&atilde;o fundamental da onda, podemos determinar o comprimento da onda pedida:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;v=%5Clambda%5Ccdot&amp;space;f\" alt=\"\\dpi{100} \\large v=\\lambda\\cdot f\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;v=%5Clambda%5Ccdot%5Cfrac%7B1%7D%7BT%7D\" alt=\"\\dpi{100} \\large v=\\lambda\\cdot\\frac{1}{T}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Clambda=v%5Ccdot&amp;space;T=500%5Ccdot20%5Ccdot%7B10%7D%5E%7B-6%7D=5%5Ccdot%7B10%7D%5E2%5Ccdot2%5Ccdot10%5Ccdot%7B10%7D%5E%7B-6%7D\" alt=\"\\dpi{100} \\large \\lambda=v\\cdot T=500\\cdot20\\cdot{10}^{-6}=5\\cdot{10}^2\\cdot2\\cdot10\\cdot{10}^{-6}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Clambda=10%5Ccdot%7B10%7D%5E3%5Ccdot%7B10%7D%5E%7B-6%7D=1%5Ccdot%7B10%7D%5E%7B-2%7D=10%5Ccdot%7B10%7D%5E%7B-3%7D=10%5C&amp;space;mm\" alt=\"\\dpi{100} \\large \\lambda=10\\cdot{10}^3\\cdot{10}^{-6}=1\\cdot{10}^{-2}=10\\cdot{10}^{-3}=10\\ mm\" align=\"absmiddle\"><\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: D<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-34\"><strong>Quest&atilde;o 34<\/strong><\/h3><p>Um objeto de massa <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;m=500g\" alt=\"\\dpi{100} \\large m=500g\" align=\"absmiddle\"> recebe uma certa quantidade de calor <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q\" alt=\"\\dpi{100} \\large Q\" align=\"absmiddle\"> e, com isso, sofre uma varia&ccedil;&atilde;o de temperatura <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;T\" alt=\"\\dpi{100} \\large \\Delta T\" align=\"absmiddle\">. A rela&ccedil;&atilde;o <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5CDelta&amp;space;T\" alt=\"\\dpi{100} \\large \\Delta T\" align=\"absmiddle\"> e <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q\" alt=\"\\dpi{100} \\large Q\" align=\"absmiddle\"> est&aacute; representada no gr&aacute;fico a seguir.<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/11\/image25.png\" alt=\"\" class=\"wp-image-33012\"><\/figure><\/div><p>Assinale a alternativa que apresenta corretamente o valor do calor espec&iacute;fico <em>C<\/em> desse objeto.<\/p><p>a) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;c=2J\/g%5Ccdot&amp;space;%5Cdegree&amp;space;C\" alt=\"\\dpi{100} \\large c=2J\/g\\cdot \\degree C\" align=\"absmiddle\"><\/p><p>b) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;c=4J\/g%5Ccdot&amp;space;%5Cdegree&amp;space;C\" alt=\"\\dpi{100} \\large c=4J\/g\\cdot \\degree C\" align=\"absmiddle\"><\/p><p>c) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;c=8J\/g%5Ccdot&amp;space;%5Cdegree&amp;space;C\" alt=\"\\dpi{100} \\large c=8J\/g\\cdot \\degree C\" align=\"absmiddle\"><\/p><p>d) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;c=16J\/g%5Ccdot&amp;space;%5Cdegree&amp;space;C\" alt=\"\\dpi{100} \\large c=16J\/g\\cdot \\degree C\" align=\"absmiddle\"><\/p><p>e) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;c=20J\/g%5Ccdot&amp;space;%5Cdegree&amp;space;C\" alt=\"\\dpi{100} \\large c=20J\/g\\cdot \\degree C\" align=\"absmiddle\"><\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-6\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>Podemos aplicar a equa&ccedil;&atilde;o fundamental da calorimetria entre dois pontos do gr&aacute;fico para determinarmos o calor espec&iacute;fico pedido. Note que o objeto recebe <em>40kJ<\/em> para que sua temperatura varie de <em>20&deg;C<\/em>:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Q=m%5Ccdot&amp;space;c%5Ccdot&amp;space;%5CDelta&amp;space;%5Ctheta\" alt=\"\\dpi{100} \\large Q=m\\cdot c\\cdot \\Delta \\theta\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;c=%5Cfrac%7BQ%7D%7Bm%5Ccdot&amp;space;%5CDelta&amp;space;%5Ctheta&amp;space;%7D=%5Cfrac%7B40%5Ccdot&amp;space;10%5E%7B3%7D%7D%7B500%5Ccdot&amp;space;20%7D=%5Cfrac%7B40%5Ccdot&amp;space;10%5E%7B3%7D%7D%7B5%5Ccdot&amp;space;10%5E%7B2%7D%5Ccdot&amp;space;2%5Ccdot&amp;space;10%7D=%5Cfrac%7B40%5Ccdot&amp;space;%5Ccancel%7B10%5E%7B3%7D%7D%7D%7B10%5Ccdot&amp;space;%5Ccancel&amp;space;%7B10%5E%7B3%7D%7D%7D\" alt=\"\\dpi{100} \\large c=\\frac{Q}{m\\cdot \\Delta \\theta }=\\frac{40\\cdot 10^{3}}{500\\cdot 20}=\\frac{40\\cdot 10^{3}}{5\\cdot 10^{2}\\cdot 2\\cdot 10}=\\frac{40\\cdot \\cancel{10^{3}}}{10\\cdot \\cancel {10^{3}}}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;c=4%5C&amp;space;cal\/g%5Ccdot&amp;space;%5Cdegree&amp;space;C\" alt=\"\\dpi{100} \\large c=4\\ cal\/g\\cdot \\degree C\" align=\"absmiddle\"><\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: B<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-35\"><strong>Quest&atilde;o 35<\/strong><\/h3><p>Um objeto de massa <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;m=10kg\" alt=\"\\dpi{100} \\large m=10kg\" align=\"absmiddle\"> est&aacute; suspenso por dois cabos que exercem tra&ccedil;&otilde;es <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Coverrightarrow%7BT_%7B1%7D%7D\" alt=\"\\dpi{100} \\large \\overrightarrow{T_{1}}\" align=\"absmiddle\"> e <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Coverrightarrow%7BT_%7B2%7D%7D\" alt=\"\\dpi{100} \\large \\overrightarrow{T_{2}}\" align=\"absmiddle\"> de mesma intensidade T, de modo que <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Cleft&amp;space;%7C&amp;space;%5Coverrightarrow%7BT_%7B1%7D%7D&amp;space;%5Cright&amp;space;%7C&amp;space;=&amp;space;%5Cleft&amp;space;%7C&amp;space;%5Coverrightarrow%7BT_%7B2%7D%7D&amp;space;%5Cright&amp;space;%7C&amp;space;=&amp;space;T\" alt=\"\\dpi{100} \\large \\left | \\overrightarrow{T_{1}} \\right | = \\left | \\overrightarrow{T_{2}} \\right | = T\" align=\"absmiddle\">. As tra&ccedil;&otilde;es exercidas pelos cabos est&atilde;o dispostas conforme mostra a figura ao lado, fazendo um &acirc;ngulo de 30&deg; com a dire&ccedil;&atilde;o horizontal. O objeto est&aacute; em equil&iacute;brio est&aacute;tico e sujeito &agrave; atra&ccedil;&atilde;o gravitacional da Terra. Nesse local, a acelera&ccedil;&atilde;o gravitacional &eacute; <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;g=10m\/s%5E%7B2%7D\" alt=\"\\dpi{100} \\large g=10m\/s^{2}\" align=\"absmiddle\">.<\/p><div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/cdn.blog.estrategiavestibulares.com.br\/vestibulares\/wp-content\/uploads\/2019\/11\/image26.png\" alt=\"\" class=\"wp-image-33013\"><\/figure><\/div><p>As medi&ccedil;&otilde;es no local s&atilde;o executadas por um observador inercial. Sabe-se que <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;sen%5C&amp;space;30%5Cdegree&amp;space;=&amp;space;cos%5C&amp;space;60%5Cdegree=1\/2\" alt=\"\\dpi{100} \\large sen\\ 30\\degree = cos\\ 60\\degree=1\/2\" align=\"absmiddle\"> e <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;sen%5C&amp;space;60%5Cdegree=cos%5C&amp;space;30%5Cdegree=%5Csqrt%7B3%7D\/2\" alt=\"\\dpi{100} \\large sen\\ 60\\degree=cos\\ 30\\degree=\\sqrt{3}\/2\" align=\"absmiddle\">.<\/p><p>Levando em considera&ccedil;&atilde;o os dados apresentados, assinale a alternativa que apresenta corretamente o valor do m&oacute;dulo da tra&ccedil;&atilde;o exercida por cada cabo.<\/p><p>a) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T=%5Cfrac%7B50%5Csqrt3%7D%7B3%7D%5C&amp;space;N\" alt=\"\\dpi{100} \\large T=\\frac{50\\sqrt3}{3}\\ N\" align=\"absmiddle\"><\/p><p>b) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T=%5Cfrac%7B100%5Csqrt3%7D%7B3%7D%5C&amp;space;N\" alt=\"\\dpi{100} \\large T=\\frac{100\\sqrt3}{3}\\ N\" align=\"absmiddle\"><\/p><p>c) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T=100%5C&amp;space;N\" alt=\"\\dpi{100} \\large T=100\\ N\" align=\"absmiddle\"><\/p><p>d) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T=%5Cfrac%7B200%5Csqrt3%7D%7B3%7D%5C&amp;space;N\" alt=\"\\dpi{100} \\large T=\\frac{200\\sqrt3}{3}\\ N\" align=\"absmiddle\"><\/p><p>e) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T=200%5C&amp;space;N\" alt=\"\\dpi{100} \\large T=200\\ N\" align=\"absmiddle\"><\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-7\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>Se o objeto est&aacute; em equil&iacute;brio, temos que as componentes horizontais de <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T_1\" alt=\"\\dpi{100} \\large T_1\" align=\"absmiddle\"> e <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T_2\" alt=\"\\dpi{100} \\large T_2\" align=\"absmiddle\"> t&ecirc;m a mesma dire&ccedil;&atilde;o, mesmo m&oacute;dulo e sentidos opostos. Al&eacute;m disso, a soma das duas componentes verticais ter&aacute; mesmo m&oacute;dulo que o peso do objeto, para que se estabele&ccedil;a o equil&iacute;brio de for&ccedil;as na vertical:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T_%7B1,y%7D+T_%7B2,y%7D=P\" alt=\"\\dpi{100} \\large T_{1,y}+T_{2,y}=P\" align=\"absmiddle\"><\/p><p>Se as duas tra&ccedil;&otilde;es fazem um &acirc;ngulo de 30&deg; com a horizontal e tem o mesmo m&oacute;dulo, podemos escrever:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T_1%5Ccdot&amp;space;sen%5Cleft(30%5Cright)+T_2%5Ccdot&amp;space;sen%5Cleft(30%5Cright)=P\" alt=\"\\dpi{100} \\large T_1\\cdot sen\\left(30\\right)+T_2\\cdot sen\\left(30\\right)=P\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T%5Ccdot&amp;space;sen%5Cleft(30%5Cright)+T%5Ccdot&amp;space;sen%5Cleft(30%5Cright)=P\" alt=\"\\dpi{100} \\large T\\cdot sen\\left(30\\right)+T\\cdot sen\\left(30\\right)=P\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;2%5Ccdot&amp;space;T%5Ccdot&amp;space;sen%5Cleft(30%5Cright)=P\" alt=\"\\dpi{100} \\large 2\\cdot T\\cdot sen\\left(30\\right)=P\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;2%5Ccdot&amp;space;T%5Ccdot%5Cfrac%7B1%7D%7B2%7D=10%5Ccdot10\" alt=\"\\dpi{100} \\large 2\\cdot T\\cdot\\frac{1}{2}=10\\cdot10\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;T=100%5C&amp;space;N\" alt=\"\\dpi{100} \\large T=100\\ N\" align=\"absmiddle\"><\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: C<\/strong><\/p><h3 class=\"wp-block-heading\" id=\"h-questao-36\"><strong>Quest&atilde;o 36<\/strong><\/h3><p>Uma for&ccedil;a de m&oacute;dulo <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;F\" alt=\"\\dpi{100} \\large F\" align=\"absmiddle\"> &eacute; aplicada perpendicularmente sobre uma superf&iacute;cie de &aacute;rea <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;A\" alt=\"\\dpi{100} \\large A\" align=\"absmiddle\">, gerando uma press&atilde;o de valor <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Cmathbit%7BP%7D_%5Cmathbf%7B1%7D\" alt=\"\\dpi{100} \\large \\mathbit{P}_\\mathbf{1}\" align=\"absmiddle\">. Com base nesses dados, assinale a alternativa que apresenta corretamente o valor da rela&ccedil;&atilde;o entre <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;%5Cmathbit%7BP%7D_%5Cmathbf%7B1%7D\" alt=\"\\dpi{100} \\large \\mathbit{P}_\\mathbf{1}\" align=\"absmiddle\"> e <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_2\" alt=\"\\dpi{100} \\large P_2\" align=\"absmiddle\">.<\/p><p>a) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_2=P_1\/2\" alt=\"\\dpi{100} \\large P_2=P_1\/2\" align=\"absmiddle\"><\/p><p>b) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_2=P_1\" alt=\"\\dpi{100} \\large P_2=P_1\" align=\"absmiddle\"><\/p><p>c) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_2=%7B2%5C&amp;space;P%7D_1\" alt=\"\\dpi{100} \\large P_2={2\\ P}_1\" align=\"absmiddle\"><\/p><p>d) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_2=%7B4%5C&amp;space;P%7D_1\" alt=\"\\dpi{100} \\large P_2={4\\ P}_1\" align=\"absmiddle\"><\/p><p>e) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_2=%7B8%5C&amp;space;P%7D_1\" alt=\"\\dpi{100} \\large P_2={8\\ P}_1\" align=\"absmiddle\"><\/p><h3 class=\"wp-block-heading\" id=\"h-resolucao-comentada-8\"><strong>Resolu&ccedil;&atilde;o Comentada<\/strong><\/h3><p>Pela defini&ccedil;&atilde;o da press&atilde;o exercida por uma for&ccedil;a perpendicular a uma superf&iacute;cie, temos:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;Pressao=%5Cfrac%7BForca%7D%7BArea%7D\" alt=\"\\dpi{100} \\large Pressao=\\frac{Forca}{Area}\" align=\"absmiddle\"><\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_1=%5Cfrac%7BF%7D%7BA%7D\" alt=\"\\dpi{100} \\large P_1=\\frac{F}{A}\" align=\"absmiddle\"><\/p><p>E para a segunda situa&ccedil;&atilde;o:<\/p><p><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/svg.latex?%5Cdpi%7B100%7D&amp;space;%5Clarge&amp;space;P_2=%5Cfrac%7B4%5Ccdot&amp;space;F%7D%7B%5Cfrac%7BA%7D%7B2%7D%7D=%5Cfrac%7B4%5Ccdot&amp;space;F%7D%7B%5Cfrac%7BA%7D%7B2%7D%7D=%5Cfrac%7B4%5Ccdot&amp;space;F%7D%7B1%7D%5Ccdot%5Cfrac%7B2%7D%7BA%7D=8%5Ccdot%5Cfrac%7BF%7D%7BA%7D=8%5Ccdot&amp;space;P_1\" alt=\"\\dpi{100} \\large P_2=\\frac{4\\cdot F}{\\frac{A}{2}}=\\frac{4\\cdot F}{\\frac{A}{2}}=\\frac{4\\cdot F}{1}\\cdot\\frac{2}{A}=8\\cdot\\frac{F}{A}=8\\cdot P_1\" align=\"absmiddle\"><\/p><p class=\"has-light-green-cyan-background-color has-background\"><strong>Gabarito: E<\/strong><\/p><p>Conte comigo em sua caminhada, e para ficar sabendo de todas as not&iacute;cias relativas aos mais diversos vestibulares ocorrendo em nosso pa&iacute;s, convido voc&ecirc; a seguir as m&iacute;dias sociais, cursos e <a href=\"https:\/\/vestibulares.estrategia.com\/portal\/category\/simulado\/\" target=\"_blank\">simulados<\/a> do Estrat&eacute;gia Vestibulares. Sinta-se tamb&eacute;m convidado a seguir o meu perfil pessoal, no qual trarei quest&otilde;es resolvidas e mais dicas para sua prepara&ccedil;&atilde;o.<\/p><div class=\"wp-block-buttons is-content-justification-center is-layout-flex wp-block-buttons-is-layout-flex\"><\/div><p><\/p><p>\n\n\n\n\n\n<a id=\"cta\" class=\"cta-imagem\" href=\"https:\/\/vestibulares.estrategia.com\/cursos\/\" target=\"blank\">\n                <img decoding=\"async\" width=\"100%\" src=\"https:\/\/vestibulares.estrategia.com\/portal\/wp-content\/uploads\/2025\/07\/ESTRATEGIA-2.jpg\" alt=\"\" title=\"ESTRAT\u00c9GIA 2\">\n        <\/a>\n<\/p><\/p>\n","protected":false},"excerpt":{"rendered":"Ol&aacute;, caro aluno. Seja Bem-Vindo. Escrevo este artigo para disponibilizar a voc&ecirc; as quest&otilde;es de F&iacute;sica da prova&hellip;\n","protected":false},"author":18,"featured_media":33016,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"wl_entities_gutenberg":"","footnotes":""},"categories":[28],"tags":[],"wl_entity_type":[732],"class_list":{"0":"post-31787","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-fisica","8":"wl_entity_type-article"},"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v25.9 (Yoast SEO v25.9) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Gabarito UFPR 2020 \u2013 F\u00edsica \u2013 Resolu\u00e7\u00e3o Comentada<\/title>\n<meta name=\"description\" content=\"Voc\u00ea participou do Vestibular UFPR 2020? 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